SSC & PSC Questions From Time and Work

Welcome to the PSC and SSC study materials section by GJR Institute (G_overnmentJ_obsR_ecruitment.in). Today, I will teach you how to solve questions from the Time & Work topic.

Rajeev Joseph, a degree student from Kottayam, asked, "Sir, can you suggest one critical section in arithmetic to never miss for a Kerala PSC examination?"

Rajeev is preparing for degree-level Kerala PSC examinations. He asked this question in the comment section of GJR Institute (G_overnmentJ_obsR_ecruitment.in).

Arti Sharma from Delhi asked, "Sir, I am preparing for the SSC CGL examination. Can you share the tip to solve Work and Time questions faster?"

Time and Work is the most common section in the SSC and State PSC Exam Question Papers.

If you are seriously preparing for competitive examinations, you cannot complete your preparation without covering the questions on Work and Time.

I suggest you go through the previous SSC and PSC question papers, and you can find at least one question from this category.

Revathi Naidu, an online student at GJR Institute (G_overnmentJ_obsR_ecruitment.in), said, "Sir, I checked many Time and Work SSC questions. They look difficult. Is there a shortcut to find the answer?"

Arun Senthil, an online student at GJR Institute (G_overnmentJ_obsR_ecruitment.in), asked, "Sir, TNPSC asks questions from the Time and Work topic. Can you provide a list of formulas to resolve them in seconds?"

Arun Senthil is preparing for the degree-level examinations by the Tamil Nadu Public Service Commission.

The questions may appear hard, but you can answer every question that falls under the category of Time and Work with preparation.

That is the primary reason I prepared this study material for you.

This tutorial will help you learn everything about Time and Work problems. I will teach you all the Time and Work formulas to help you solve the questions immediately.

The first part of this guide covers the concepts. The second part covers frequently asked SSC and PSC questions in the Work and Time category.

I believe those preparing for various government jobs through SSC, PSC, and UPSC may find this guide helpful.

• If a man completes his work in 'n' days, work done by him in one day is 1/n.
  
  
• If the work done by a man in one day is 1/n, he can finish the complete work in n days.
  
  
• Time and work are always inversely proportional to each other.
  
  
• If M1 persons can do W1 work in D1 days and M2 persons can do W2 work in D2 days, the general formula to find the total work or total time is :
  
  M1 * D1 * W2 = M2 * D2 * W1
  
  

The above concepts are necessary for solving problems in Time and Work aptitude questions. Now, let us check how to solve these questions using shortcuts.

1.  A can finish a specific work in 10 days and B can do the same in 20 days. Find the time required to complete the work by both A and B together.
   
   Ans:
   Work done in a day by A = 1/(10)
   
   Work done by B in a day = 1/(20)
   
   Work done in a day by both A and B together = 1/(10) + 1/(20) = (2 + 1)/(20) =3/20
   
   
   
   { Here, we took the LCM of both denominators. To learn more about it, click the link below.
   
   Apply the first law explained in this tutorial. Time and work are inversely proportional to each other.
   
   => reverse of 3/20 => 20/3 days
   
   
2. 40 persons make 60 bricks in 3 hours. If 8 persons leave the work, how many bricks will be made by the remaining persons in the next 6 hours?
   
   Ans:
   Here we need to use the formula M1 * D1 * W2 = M2 * D2 * W1
   
   Here M1 = 40 M2= 32 W1 = 60 D1= 3 D2= 6 W2 = ?
   
   

      
           
     
             M2  * D2 * W1
     
     w2 =   ------------------
     
             M1 * D1
   
   
   

   
   
   => W2 = (32 * 6 * 60)/ (40 *3) = 96 bricks
   
   
3. If X can do a piece of work in 25 days, and Y can finish it in 20 days. They worked together for 5 days and then X left. How many days Y will take to complete the work?
   
   Ans:
   Work was done by X in a day = 1/25
   
   Work was done by Y in a day =1/20
   
   Work done by both X and Y in 5 days = 5 * (1/25 + 1/20) = 9/20
   
   Remaining work = 1 - (9/20) =11/20
   
   Y finish 1/20 work in a day. So to finish 11/20 work, Y needs 11 more days.